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Proof step 5 from proof at-put-first-05 (conclusion)

⊦ (st[r -- (sk ' + sk0 '), val][st[r -- sk] .refval -- (sk0 ' + sk1 ')]) = (st[r -- (sk ' + sk0 '), val][val .refval -- sk1 '])

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 1:
⊦ st[r -- sk '] = st[r -- sk]
Proof step 4:
⊦ (st[r -- (sk ' + sk0 '), val][st[r -- sk] .refval -- (sk0 ' + sk1 ')]) = (st[r -- (sk ' + sk0 '), val][val .refval -- sk1])

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]