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Proof step 4 from proof at-put-first-rec-01 (conclusion)

⊦ sk ≠ sk0 → (st[r -- sk, val][r0 -- (sk0 ' + sk1 ')]) = (st[r -- sk, val][st[r0 -- sk0] .refval -- sk1])

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
⊦ sk = sk0, (st[r -- sk, val][r0 -- (sk0 ' + sk1 ')]) = (st[r -- sk, val][st[r0 -- sk0] .refval -- sk1])

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]