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Proof step 3 from proof at-put-first-rec (conclusion)

⊦ sk ≠ sk0 ∧ sks ≠ [] → (st[r -- sk, val][r0 -- (sk0 ' + sks)]) = (st[r -- sk, val][st[r0 -- sk0] .refval -- sks])

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
⊦ sk = sk0, sks = [], (st[r -- sk, val][r0 -- (sk0 ' + sks)]) = (st[r -- sk, val][st[r0 -- sk0] .refval -- sks])

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]