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Proof step 5 from proof at-put-first (conclusion)

⊦ rk = jvmref -- sk ∧ sks ≠ [] → (st[rk, val][sk ' + sks]) = (st[rk, val][val .refval -- sks])

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
⊦ (st[jvmref -- sk, val][sk ' + sks]) = (st[jvmref -- sk, val][val .refval -- sks]), sks = []

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]