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Proof step 3 from proof at-put-keys-01 (previous step)

∀ sk, sk0, st, r, val, r0. sk = sk0 ∨ (st[r -- (sks0 + sk '), val][r0 -- sk0]) = st[r0 -- sk0] ⊦ sk = sk0, (st[st[r -- sk1] .refval -- (sks0 + sk '), val][r0 -- sk0]) = st[r0 -- sk0]

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

[EXRARG : pos: left 1, [QUANTTERMLIST : (sk, sk0, st, st[r -- sk1] .refval, val, r0)]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (sk, sk0, st, st[r -- sk1] .refval, val, r0)]]