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Proof step 8 from proof at-put-keys-01 (conclusion)

⊦ sk ≠ sk0 → (st[r -- (sks + sk '), val][r0 -- sk0]) = st[r0 -- sk0]

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]