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Proof step 3 from proof at-put-keys-02 (conclusion)

⊦ sk0 ≠ sks .last ∧ sks ≠ [] → (st[r -- sks, val][r0 -- sk0]) = st[r0 -- sk0]

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
⊦ sk0 = sks .last, sks = [], (st[r -- sks, val][r0 -- sk0]) = st[r0 -- sk0]

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]