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Proof step 5 from proof at-put-last-other-01 (previous step)

r0 ≠ st[r -- sks .butlast] .refval ∨ sk ≠ sks .last ⊦ (st[r -- sks, val][r0 -- sk]) = st[r0 -- sk], # sks = 1, sks = []

User applied rule insert elim lemma

And obtained the following new goals

Proof step 4:
sks = sks0 + sk0 ', r0 ≠ st[r -- sks0] .refval ∨ sk ≠ sk0 ⊦ (st[r -- sks, val][r0 -- sk]) = st[r0 -- sk], # sks = 1, sks = []

Rule argument

[speclemmaarg: sks ≠ [] ,sk = sks .last ∧ sks0 = sks .butlast ↔ sks = sks0 + sk ' ,[sks, sk, sks0] → [sks, sk0, sks0] ,T ,list-last ,storekeys ,last-elim ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPELIM : sks ≠ [] ⊦ sk = sks .last ∧ sks0 = sks .butlast ↔ sks = sks0 + sk '])], [EXTRATERMS : (sks, sk0, sks0)]]