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Proof step 19 from proof at-put-other-01 (previous step)

∀ st, r, sk, val. (st[r -- sk, val][jvmref -- sks0]) = st[jvmref -- sks0] ∨ sk ∈ sks0 ⊦ jvmref -- sk0 = r -- sk, (st[r -- sk, val][(st[r -- sk, val][jvmref -- sk0]) .refval -- sks0]) = st[jvmref -- (sk0 ' + sks0)], sk = sk0, sks0 = [], sk ∈ sks0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 18:
∀ st, r, sk, val. (st[r -- sk, val][jvmref -- sks0]) = st[jvmref -- sks0] ∨ sk ∈ sks0 ⊦ (st[r -- sk, val][(st[r -- sk, val][jvmref -- sk0]) .refval -- sks0]) = st[jvmref -- (sk0 ' + sks0)], sk = sk0, sks0 = [], sk ∈ sks0

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ r -- sk = r0 -- sk0 ↔ ¬ ¬ (r = r0 ∧ sk = sk0)])]]