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Proof step 26 from proof del-put-switch (previous step)

⊦ r = r0, st[r -- sk, val] -- r0 = (st -- r0)[r -- sk, val]

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 1:
⊦ st1 = st2 ↔ (∀ rk. (rk ∈ st1 ↔ rk ∈ st2) ∧ st1[rk] = st2[rk])
Proof step 25:
⊦ r = r0, ∀ rk. (rk ∈ st[r -- sk, val] -- r0 ↔ rk ∈ (st -- r0)[r -- sk, val]) ∧ (st[r -- sk, val] -- r0)[rk] = ((st -- r0)[r -- sk, val][rk])

Rule argument

[speclemmaarg: ,st1 = st2 ↔ (∀ rk. (rk ∈ st1 ↔ rk ∈ st2) ∧ st1[rk] = st2[rk]) ,[st2, st1] → [(st -- r0)[r -- sk, val], st[r -- sk, val] -- r0] ,F ,store ,javastore ,Extension ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : ((st -- r0)[r -- sk, val], st[r -- sk, val] -- r0)]]