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Proof step 10 from proof del-put (previous step)

¬ r -- sk ∈ st[r -- sk0, val] -- r ⊦ ∅[r -- sk] = (st -- r)[r -- sk]

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
⊦ r -- sk ∈ st -- r0 ↔ ¬ ¬ (r ≠ r0 ∧ r -- sk ∈ st)
Proof step 9:
⊦ ∅[r -- sk] = (st -- r)[r -- sk]

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]