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Proof step 17 from proof del-put (previous step)

⊦ ∀ rk. (rk ∈ st[r -- sk, val] -- r ↔ rk ∈ st -- r) ∧ (st[r -- sk, val] -- r)[rk] = (st -- r)[rk]

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 16:
⊦ (rk ∈ st[r -- sk, val] -- r ↔ rk ∈ st -- r) ∧ (st[r -- sk, val] -- r)[rk] = (st -- r)[rk]

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]