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Proof step 10 from proof del-refs-size (previous step)

r -- sk ∈ st, # st ≤ # (st -- r), r ∈ st ⊦

User applied rule insert spec-lemma

And obtained the following new goals

Proof step 4:
⊦ st ⊆ st0 → # st ≤ # st0
Proof step 9:
st -- r ⊆ st -- (r -- sk) → # (st -- r) ≤ # (st -- (r -- sk)), r -- sk ∈ st, # st ≤ # (st -- r), r ∈ st ⊦

Rule argument

[speclemmaarg: ,st ⊆ st0 → # st ≤ # st0 ,[st, st0] → [st -- r, st -- (r -- sk)] ,F ,store ,javastore ,size-subset ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (st -- r, st -- (r -- sk))]]