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Proof step 12 from proof del-refs-size (previous step)

r ∈ st, # st ≤ # (st -- r) ⊦

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 2:
⊦ r ∈ st ↔ (∃ sk. r -- sk ∈ st)
Proof step 11:
∃ sk. r -- sk ∈ st, # st ≤ # (st -- r) ⊦

Rule argument

[crewrite-arg: instore, F, [st, r] → [st, r]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (st, r)]]