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Proof step 7 from proof del-refs-size (previous step)

# st = m + 1 ∧ # st ≠ 0, r -- sk ∈ st, # st ≤ # (st -- r), r ∈ st, st -- r ⊆ st -- (r -- sk) → # (st -- r) ≤ m ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
⊦ st -- r ⊆ st -- (r -- sk)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ m + n = n + m], [CSIMPSEQ : ⊦ (m + n0) + n1 = m + n0 + n1], [CSIMPSEQ : ⊦ m + n ≤ m ↔ n = 0], [CSIMPFORWARD : ⊦ n ≤ n0 ∧ n0 ≤ n1 → n ≤ n1], [CSIMPSEQ : ⊦ # st = 0 ↔ st = ∅])]]