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Proof step 5 from proof del-subset-del (previous step)

⊦ ∀ rk. rk ∈ st -- r → rk ∈ st -- (r -- sk) ∧ (st -- r)[rk] = (st -- (r -- sk))[rk]

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
rk ∈ st -- r ⊦ rk ∈ st -- (r -- sk) ∧ (st -- r)[rk] = (st -- (r -- sk))[rk]

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]