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Proof step 28 from proof del-switch (previous step)

r0 ≠ r1 ⊦ (st -- r)[r1 -- sk] = (st -- r0 -- r)[r1 -- sk]

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 27:
⊦ r0 = r1, (st -- r)[r1 -- sk] = (st -- r0 -- r)[r1 -- sk]

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]