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Proof step 32 from proof del-switch (previous step)

⊦ ∀ rk. (rk ∈ st -- r -- r0 ↔ rk ∈ st -- r0 -- r) ∧ (st -- r -- r0)[rk] = (st -- r0 -- r)[rk]

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 31:
⊦ (rk ∈ st -- r -- r0 ↔ rk ∈ st -- r0 -- r) ∧ (st -- r -- r0)[rk] = (st -- r0 -- r)[rk]

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]