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Proof step 7 from proof exists-twonew (previous step)

jvmref < r, r < r0, jvmref < r0, ∀ r. ∃ r0. r < r0, ∀ r0. r0 ∈ st → r0 < r ⊦ r0 -- sk ∈ st → r1 ≠ r0, r = r0, r0 = jvmref, r = jvmref

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
⊦ r -- sk ∈ st → r ∈ st
Proof step 6:
r0 -- sk ∈ st, jvmref < r, r < r0, jvmref < r0, r0 ∈ st, ∀ r. ∃ r0. r < r0, ∀ r0. r0 ∈ st → r0 < r ⊦ r = r0, r0 = jvmref, r = jvmref

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]