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Proof step 1 from proof extension-neqrefs (conclusion)

⊦ ¬ (∀ sk. (r -- sk ∈ st ↔ r0 -- sk ∈ st) ∧ st[r -- sk] = st[r0 -- sk]) → r ≠ r0

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]