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Proof step 13 from proof in-list-put (previous step)

rk = r0 -- sk ⊦ sks = [], r -- sks ∈ st[rk, val] ↔ r -- sks ∈ st, sk ∈ sks

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 12:
⊦ sks = [], r -- sks ∈ st[r0 -- sk, val] ↔ r -- sks ∈ st, sk ∈ sks

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]