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Proof step 3 from proof in-put-keys-02 (previous step)

str ≠ str0 ⊦ r0 -- mkfs(class, ty, str .field) ' ∈ st[r -- (sks + mkfs(class0, ty0, str0 .field) ' '), val] ↔ r0 -- mkfs(class, ty, str .field) ' ∈ st

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
⊦ str = str0, r0 -- mkfs(class, ty, str .field) ' ∈ st[r -- (sks + mkfs(class0, ty0, str0 .field) ' '), val] ↔ r0 -- mkfs(class, ty, str .field) ' ∈ st

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]