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Proof step 21 from proof in-put (previous step)

⊦ # sks = 1, sks = [], r0 -- sk ∈ st[r -- sks, val] ↔ r0 -- sk ∈ st ∨ r0 = st[r -- sks .butlast] .refval ∧ sk = sks .last

User applied rule structural induction

And obtained the following new goals

Proof step 20:
∀ r0, sk, st, r, val. # sks0 = 1 ∨ sks0 = [] ∨ (r0 -- sk ∈ st[r -- sks0, val] ↔ r0 -- sk ∈ st ∨ r0 = st[r -- sks0 .butlast] .refval ∧ sk = sks0 .last) ⊦ # (sk0 + sks0) = 1, sk0 + sks0 = [], r0 -- sk ∈ st[r -- (sk0 + sks0), val] ↔ r0 -- sk ∈ st ∨ r0 = st[r -- (sk0 + sks0) .butlast] .refval ∧ sk = (sk0 + sks0) .last

Rule argument

[VARWITHVARSEQSARG : sks, ()]

Additional information

[[CONCRETESIMPRULES : ([CSIMPGEN : storekeys generated by [], +;])]]