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Proof step 8 from proof in-put (previous step)

# sks0 = 1 ⊦ sks0 = [], r0 -- sk ∈ st[r -- (sk0 ' + sks0), val] ↔ r0 -- sk ∈ st ∨ r0 = st[r -- (sk0 ' + sks0 .butlast)] .refval ∧ sk = sks0 .last

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 1:
⊦ # sks = 1 ↔ sks = sks .first + []
Proof step 7:
sks0 = sks0 .first + [] ⊦ sks0 = [], r0 -- sk ∈ st[r -- (sk0 ' + sks0), val] ↔ r0 -- sk ∈ st ∨ r0 = st[r -- (sk0 ' + sks0 .butlast)] .refval ∧ sk = sks0 .last

Rule argument

[speclemmaarg: ,# sks = 1 ↔ sks = sks .first + [] ,[sks] → [sks0] ,F ,list-data ,storekeys ,lf-01 ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (sks0)]]