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Proof step 19 from proof init-put-23 (previous step)

rk .ref = jvmref, rk .key .fs .type = void_type, rk .key .fs .field = `initstate' .field, is_fskey(rk .key), rk ∈ st, ∀ rk0. rk0 ∈ st ∧ rk0 .ref = jvmref ∧ ¬ is_indexkey(rk0 .key) ∧ rk0 .key .fs .type = void_type ∧ rk0 .key .fs .field = `initstate' .field → st[rk0] ≠ initval(undone) ∧ st[rk0] ≠ initval(error) ⊦ r = jvmref, rk = r -- sk, _uninit ∈ st, st[rk] ≠ initval(undone) ∧ st[rk] ≠ initval(error)

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 18:
rk = r0 -- sk0, r0 = jvmref, sk0 .fs .type = void_type, sk0 .fs .field = `initstate' .field, is_fskey(sk0), rk ∈ st, ∀ rk0. rk0 ∈ st ∧ rk0 .ref = jvmref ∧ ¬ is_indexkey(rk0 .key) ∧ rk0 .key .fs .type = void_type ∧ rk0 .key .fs .field = `initstate' .field → st[rk0] ≠ initval(undone) ∧ st[rk0] ≠ initval(error) ⊦ r = jvmref, rk = r -- sk, _uninit ∈ st, st[rk] ≠ initval(undone) ∧ st[rk] ≠ initval(error)

Rule argument

[speclemmaarg: ,r = rk .ref ∧ sk = rk .key ↔ rk = r -- sk ,[rk, r, sk] → [rk, r0, sk0] ,T ,refkey , ,elim ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPELIM : ⊦ r = rk .ref ∧ sk = rk .key ↔ rk = r -- sk])], [EXTRATERMS : (rk, r0, sk0)]]