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Proof step 10 from proof instore-rec-01 (conclusion)

⊦ sks ≠ [] → (r -- (sk ' + sks) ∈ st ↔ r -- sk ∈ st ∧ st[r -- sk] .refval -- sks ∈ st)

User applied rule structural induction

And obtained the following new goals

Proof step 9:
∀ r, sk, st. sks0 ≠ [] → (r -- (sk ' + sks0) ∈ st ↔ r -- sk ∈ st ∧ st[r -- sk] .refval -- sks0 ∈ st) ⊦ sk0 + sks0 ≠ [] → (r -- (sk ' + (sk0 + sks0)) ∈ st ↔ r -- sk ∈ st ∧ st[r -- sk] .refval -- (sk0 + sks0) ∈ st)

Rule argument

[VARWITHVARSEQSARG : sks, ()]

Additional information

[[CONCRETESIMPRULES : ([CSIMPGEN : storekeys generated by [], +;])]]