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Proof step 4 from proof instore-two (previous step)

⊦ r -- (sk ' + sk0 ') ∈ st ↔ r -- sk ∈ st ∧ st[r -- sk] .refval -- sk0 ∈ st

User applied rule insert lemma

And obtained the following new goals

Proof step 2:
⊦ r -- (sk ' + sk0 ' + sks) ∈ st ↔ r -- sk ∈ st ∧ st[r -- sk] .refval -- (sk0 ' + sks) ∈ st
Proof step 3:
⊦ r -- sk ' ∈ st ↔ r -- sk ∈ st

Rule argument

[LEMMAARG : instore-rec, [r, sk, sk0, sks, st] → [r, sk, sk0, [], st]]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ sks + [] = sks], [CSIMPSEQ : ⊦ (sks + sks0) + sks1 = sks + sks0 + sks1])], [EXTRATERMS : (r, sk, sk0, [], st)]]