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Proof step 13 from proof lookup-append (previous step)

sks1 = [] ∨ (∀ sks0, st, r. sks0 = [] ∨ st[r -- (sks1 + sks0)] = st[st[r -- sks1] .refval -- sks0]) ⊦ sks0 = [], st[r -- ((sk ' + sks1) + sks0)] = st[st[r -- (sk ' + sks1)] .refval -- sks0]

User applied rule cut formula

And obtained the following new goals

Proof step 4:
sks1 = [], sks1 = [] ∨ (∀ sks0, st, r. sks0 = [] ∨ st[r -- (sks1 + sks0)] = st[st[r -- sks1] .refval -- sks0]) ⊦ sks0 = [], st[r -- ((sk ' + sks1) + sks0)] = st[st[r -- (sk ' + sks1)] .refval -- sks0]
Proof step 12:
sks1 = [] ∨ (∀ sks0, st, r. sks0 = [] ∨ st[r -- (sks1 + sks0)] = st[st[r -- sks1] .refval -- sks0]) ⊦ sks1 = [], sks0 = [], st[r -- ((sk ' + sks1) + sks0)] = st[st[r -- (sk ' + sks1)] .refval -- sks0]

Rule argument

[fma-arg: sks1 = []]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRAFMAS : (sks1 = [])]]