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Proof step 16 from proof lookup-append (conclusion)

⊦ sks ≠ [] ∧ sks0 ≠ [] → st[r -- (sks + sks0)] = st[st[r -- sks] .refval -- sks0]

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 15:
⊦ sks = [], sks0 = [], st[r -- (sks + sks0)] = st[st[r -- sks] .refval -- sks0]

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]