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Proof step 11 from proof lookup-list-intro-01 (previous step)

sks0 ≠ [], ∀ st, r, sk0. st[st[r -- sks0] .refval -- sk0] = st[r -- (sks0 + sk0 ')] ⊦ sks0 = [], st[st[st[r -- sk] .refval -- sks0] .refval -- sk0] = st[r -- ((sk ' + sks0) + sk0 ')]

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 10:
∀ st, r, sk0. st[st[r -- sks0] .refval -- sk0] = st[r -- (sks0 + sk0 ')] ⊦ sks0 = [], st[st[st[r -- sk] .refval -- sks0] .refval -- sk0] = st[r -- ((sk ' + sks0) + sk0 ')]

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]