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Proof step 15 from proof lookup-list-intro-01 (previous step)

∀ st, r, sk0. sks0 = [] ∨ st[st[r -- sks0] .refval -- sk0] = st[r -- (sks0 + sk0 ')] ⊦ sk + sks0 = [], st[st[r -- (sk + sks0)] .refval -- sk0] = st[r -- ((sk + sks0) + sk0 ')]

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 14:
sks0 = [] ∨ (∀ st, r, sk0. st[st[r -- sks0] .refval -- sk0] = st[r -- (sks0 + sk0 ')]) ⊦ st[st[r -- (sk ' + sks0)] .refval -- sk0] = st[r -- ((sk ' + sks0) + sk0 ')]

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ (sks + sks0) + sks1 = sks + sks0 + sks1], [CSIMPSEQ : ⊦ sk ' + sks ≠ []], [CSIMPSEQ : ⊦ sk + sks = sk ' + sks])]]