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Proof step 6 from proof lookup-list-put-ex (previous step)

⊦ val = st[r0 -- sk], ∃ sks, sks0. sk ' = sks + sk ' + sks0 ∧ st[r0 -- sks] .refval = r0

User applied rule exists right

And obtained the following new goals

Proof step 5:
⊦ st[r -- []] = refval(r)

Rule argument

[EXRARG : pos: right 2, [extquanttermlist: ([], [])abort:F, discard:T, computed:F]]

Additional information

[[CONCRETESIMPRULES : ([CSIMPNAMEDSEQ : list, storekeys, Nil, ⊦ [] + sks = sks], [CSIMPNAMEDSEQ : list, storekeys, app, ⊦ sks + [] = sks], [CSIMPNAMEDSEQ : list, storekeys, a, ⊦ (sks + sks0) + sks1 = sks + sks0 + sks1], [CSIMPNAMEDSEQ : list, storekeys, c-04, ⊦ sk ' = sk0 ' ↔ sk = sk0], [CSIMPNAMEDSEQ : javavalue, , sel-09, ⊦ refval(r) .refval = r])], [EXTRATERMS : ([], [])]]