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Proof step 8 from proof lookup-list-put-ex (previous step)

⊦ (st[r0 -- sk, val][r -- sk0]) = st[r -- sk0], ∃ sks, sks0. sk0 ' = sks + sk ' + sks0 ∧ st[r -- sks] .refval = r0

Heuristic weak cut applied rule cut formula

And obtained the following new goals

Proof step 7:
r -- sk0 = r0 -- sk ⊦ (st[r0 -- sk, val][r -- sk0]) = st[r -- sk0], ∃ sks, sks0. sk0 ' = sks + sk ' + sks0 ∧ st[r -- sks] .refval = r0

Rule argument

[fma-arg: r -- sk0 = r0 -- sk]

Additional information

[[CONCRETESIMPRULES : ([CSIMPNAMEDSEQ : refkey, , inj-01, ⊦ r -- sk = r0 -- sk0 ↔ ¬ ¬ (r = r0 ∧ sk = sk0)], [CSIMPNAMEDSEQ : javastore, , look-ins, ⊦ r ≠ r0 → (st[r0 -- sk0, val] [r -- sk ] ) = st[r -- sk]], [CSIMPNAMEDSEQ : javastore, , at-other-16, ⊦ sk ≠ sk0 → (st[r -- sk, val] [r0 -- sk0 ] ) = st[r0 -- sk0]])], [EXTRAFMAS : (r -- sk0 = r0 -- sk)]]