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Proof step 4 from proof lookup-put-keys (conclusion)

⊦ sk ≠ sk0 ∧ sks0 ≠ [] → (st[r -- (sks + sk '), val][r0 -- (sk0 ' + sks0)]) = (st[r -- (sks + sk '), val][st[r0 -- sk0] .refval -- sks0])

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
⊦ sk = sk0, sks0 = [], (st[r -- (sks + sk '), val][r0 -- (sk0 ' + sks0)]) = (st[r -- (sks + sk '), val][st[r0 -- sk0] .refval -- sks0])

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]