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Proof step 5 from proof lookup-put-rkvs-diff-03 (conclusion)

str ≠ str0 ⊦ (st[((r -- mkfs(class, ty, ((* str)) .field) ') × val) ' + rkvs][r0 -- mkfs(class0, ty0, ((* str0)) .field) ']) = (st[rkvs][r0 -- mkfs(class0, ty0, str0 .field) '])

Special step normalize

And obtained the following new goals

Proof step 4:
str ≠ str0 ⊦ (st[((r -- mkfs(class, ty, str .field) ') × val) ' + rkvs][r0 -- mkfs(class0, ty0, str0 .field) ']) = (st[rkvs][r0 -- mkfs(class0, ty0, str0 .field) '])