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Proof step 9 from proof lookup-put-rkvs (previous step)

rkv = rk1 × val0, ∀ rk, rk0, st, val. rk = rk0 ∨ (st[rk, val][rkvs0][rk0]) = (st[rkvs0][rk0]) ⊦ rk = rk0, (st[rk, val][rk1, val0][rkvs0][rk0]) = (st[rk1, val0][rkvs0][rk0])

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 8:
∀ rk, rk0, st, val. rk = rk0 ∨ (st[rk, val][rkvs0][rk0]) = (st[rkvs0][rk0]) ⊦ rk = rk0, (st[rk, val][rk1, val0][rkvs0][rk0]) = (st[rk1, val0][rkvs0][rk0])

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]