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Proof step 5 from proof lookup-rec-refval (previous step)

sks = sk + sks0, is_referencevalue(st[r -- sks]) ⊦ sks = [], st[r -- sks] = st[st[r -- sk] .refval -- sks0]

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
is_referencevalue(st[r -- (sk ' + sks0)]) ⊦ st[r -- (sk ' + sks0)] = st[st[r -- sk] .refval -- sks0]

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ (sks + sks0) + sks1 = sks + sks0 + sks1], [CSIMPSEQ : ⊦ sk ' + sks ≠ []], [CSIMPSEQ : ⊦ sk + sks = sk ' + sks])]]