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Proof step 10 from proof maxref-exists (previous step)

r < r0, r < r2, r0 < r1, r < r1, ∀ r1. r1 ∈ st0 → r1 < r0, ∀ r. ∃ r0. r < r0 ⊦ ∀ r1. r1 ∈ st0[r -- sk, val] → r1 < r0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 9:
r < r1, r0 < r1, r < r2, r < r0, r3 ∈ st0[r -- sk, val], ∀ r. ∃ r0. r < r0, ∀ r1. r1 ∈ st0 → r1 < r0 ⊦ r3 < r0

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]