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Proof step 4 from proof mode-01 (previous step)

⊦ r = jvmref, (∃ sk. r -- sk ∈ st[_mode, val]) ↔ r ∈ st

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
⊦ r = jvmref, (∃ sk. r -- sk ∈ st) ↔ r ∈ st

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ r ≠ jvmref → ( r -- sk ∈ st[_mode, val] ↔ r -- sk ∈ st)])]]