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Proof step 6 from proof new-insert (conclusion)

⊦ newref(r, st[rk, val]) → newref(r, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 1:
⊦ newref(r, st) ↔ r ≠ jvmref ∧ (∀ rk. rk ∈ st → rk .ref ≠ r)
Proof step 5:
rk0 ∈ st, ∀ rk1. rk1 = rk ∨ rk1 ∈ st → rk1 .ref ≠ rk0 .ref ⊦ rk0 .ref = jvmref

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ rk ∈ st[rk0, val] ↔ rk = rk0 ∨ rk ∈ st])]]