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Proof step 15 from proof new-out (conclusion)

⊦ newref(r, st[_out, val]) ↔ newref(r, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 1:
⊦ newref(r, st) ↔ r ≠ jvmref ∧ (∀ rk. rk ∈ st → rk .ref ≠ r)
Proof step 14:
⊦ r ≠ jvmref ∧ (∀ rk. rk = _out ∨ rk ∈ st → rk .ref ≠ r) ↔ newref(r, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ rk ∈ st[rk0, val] ↔ rk = rk0 ∨ rk ∈ st])]]