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Proof step 11 from proof newref-02 (previous step)

r ≠ jvmref ∧ (∀ rk. rk = r0 -- sk ∨ rk ∈ st → rk .ref ≠ r) ⊦ r ≠ r0 ∧ r ≠ jvmref ∧ (∀ rk. rk ∈ st → rk .ref ≠ r)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 10:
∀ rk. rk = r0 -- sk ∨ rk ∈ st → rk .ref ≠ r ⊦ r = jvmref, (rk ∈ st → rk .ref ≠ r) ∧ r ≠ r0

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]