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Proof step 14 from proof newref-02 (previous step)

rk = r -- sk0, rk ∈ st, ∀ rk0. rk0 ∈ st → rk0 .ref ≠ r ⊦ rk = r0 -- sk, r = r0, r = jvmref

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 12:
⊦ r -- sk ∈ st → r ∈ st
Proof step 13:
r -- sk0 ∈ st, r ∈ st, ∀ rk0. rk0 ∈ st → rk0 .ref ≠ r ⊦ r = r0, r = jvmref

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ r -- sk = r0 -- sk0 ↔ ¬ ¬ (r = r0 ∧ sk = sk0)])]]