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Proof step 16 from proof newref-02 (previous step)

r ≠ r0 ∧ r ≠ jvmref ∧ (∀ rk. rk ∈ st → rk .ref ≠ r) ⊦ r ≠ jvmref ∧ (∀ rk. rk = r0 -- sk ∨ rk ∈ st → rk .ref ≠ r)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 15:
rk ∈ st, ∀ rk0. rk0 ∈ st → rk0 .ref ≠ rk .ref ⊦ rk = r0 -- sk, rk .ref = r0, rk .ref = jvmref

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ (r -- sk) .ref = r])]]