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Proof step 4 from proof newref-02 (previous step)

r -- sk0 ∈ st, r ∈ st, ∀ rk. rk = r0 -- sk ∨ rk ∈ st → rk .ref ≠ r ⊦ r = jvmref

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

[EXRARG : pos: left 3, [QUANTTERMLIST : (r -- sk0)]]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ r -- sk = r0 -- sk0 ↔ ¬ ¬ (r = r0 ∧ sk = sk0)], [CSIMPSEQ : ⊦ (r -- sk) .ref = r])], [EXTRATERMS : (r -- sk0)]]