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Proof step 8 from proof newref-02 (previous step)

∀ rk. rk = r0 -- sk ∨ rk ∈ st → rk .ref ≠ r ⊦ r = jvmref, (r -- sk0 ∈ st → r1 ≠ r) ∧ r ≠ r0

User applied rule case distinction

And obtained the following new goals

Proof step 5:
∀ rk. rk = r0 -- sk ∨ rk ∈ st → rk .ref ≠ r ⊦ r -- sk0 ∈ st → r1 ≠ r, r = jvmref
Proof step 7:
∀ rk. rk = r0 -- sk ∨ rk ∈ st → rk .ref ≠ r ⊦ r ≠ r0, r = jvmref

Rule argument

[CASEDARG : pos: right 2, ()]

Additional information

[[CONCRETESIMPRULES : ()]]