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Proof step 5 from proof newref-del (previous step)

rk = r0 -- sk, rk ∈ st -- r, ∀ rk0. rk0 ∈ st → rk0 .ref ≠ r0 ⊦ r0 = jvmref

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
⊦ r -- sk ∈ st -- r0 ↔ r ≠ r0 ∧ r -- sk ∈ st
Proof step 3:
⊦ r -- sk ∈ st → r ∈ st
Proof step 4:
r0 -- sk ∈ st, r0 ∈ st, ∀ rk0. rk0 ∈ st → rk0 .ref ≠ r0 ⊦ r0 = jvmref, r0 = r

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]