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Proof step 7 from proof newref-del (conclusion)

⊦ newref(r0, st) → newref(r0, st -- r)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 1:
⊦ newref(r, st) ↔ r ≠ jvmref ∧ (∀ rk. rk ∈ st → rk .ref ≠ r)
Proof step 6:
rk ∈ st -- r, ∀ rk0. rk0 ∈ st → rk0 .ref ≠ rk .ref ⊦ rk .ref = jvmref

Rule argument

[emptyarg]

Additional information

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