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Proof step 3 from proof newref-empty (conclusion)

⊦ newref(r, ∅) ↔ r ≠ jvmref

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 1:
⊦ ¬ newref(jvmref, st)
Proof step 2:
⊦ newref(r, st) ↔ r ≠ jvmref ∧ (∀ rk. rk ∈ st → rk .ref ≠ r)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ ¬ rk ∈ ∅])]]