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Proof step 7 from proof newref-exists (previous step)

rk ∈ st, r < rk .ref, jvmref < rk .ref, r < jvmref, ∀ r. ∃ r0. r < r0, ∀ r0. r0 ∈ st → r0 < r ⊦ rk .ref = jvmref

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 6:
rk = r1 -- sk, rk ∈ st, r < r1, jvmref < r1, r < jvmref, ∀ r. ∃ r0. r < r0, ∀ r0. r0 ∈ st → r0 < r ⊦ r1 = jvmref

Rule argument

[speclemmaarg: ,r = rk .ref ∧ sk = rk .key ↔ rk = r -- sk ,[rk, r, sk] → [rk, r1, sk] ,T ,refkey , ,elim ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPELIM : ⊦ r = rk .ref ∧ sk = rk .key ↔ rk = r -- sk])], [EXTRATERMS : (rk, r1, sk)]]